# Merge the Tools! Python Hackerrank solution

Problem: Consider the following problem: You are given a string s and an integer k. Split s into n/k subsegments where each subsegment contains k ch

Problem:

Consider the following problem:

You are given a string s and an integer k. Split s into n/k subsegments where each subsegment contains k characters. Then, for each subsegment, delete any duplicate characters in the subsegment and print the subsegment without duplicates.

Example:

Input:

`s = "AABCAAADA"k = 3`

Output:

`ABCAAD`

Explanation:

String s is split into n/k = 9/3 = 3 subsegments of length k=3:

`AABCAAADA`

The first subsegment is "AAB", which contains the duplicate characters "A". These are removed to produce the output "AB". The second subsegment is "CAA", which contains the duplicate character "A". This is removed to produce the output "CA". The third subsegment is "ADA", which contains no duplicate characters, so the output is "AD".

To solve this problem in Python, you can define a function that takes in the string s and integer k, and then implement the above algorithm to print the subsegments without duplicates.

Solution

```def merge_the_tools(string, k):
n = len(string)
num_subsegments = n // k
for i in range(num_subsegments):
subsegment = string[i*k : (i+1)*k]
unique_chars = []
for char in subsegment:
if char not in unique_chars:
unique_chars.append(char)
print(char, end="")
print()

if __name__ == '__main__':
string, k = input(), int(input())
merge_the_tools(string, k)```

The merge_the_tools function takes two arguments: a string string and an integer k. It first calculates the number of subsegments in the string by dividing the length of the string by k.

Then, it loops over each subsegment and creates a list unique_chars to store the unique characters in that subsegment. It iterates over each character in the subsegment and checks if it's already in the unique_chars list. If it's not, it adds it to the list and prints it. Finally, it prints a newline character to move to the next subsegment.

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